Analysis Basics

Take 15 minutes to prepare this exercise.

Then, if you lack ideas to begin, look at the given clue and start searching for the solution.

A detailed solution is then proposed to you.

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Question

We denote by an interval of and by and two applications defined from to that are continuous in a point

a) Prove that application is continuous in

b) Prove that if application is continuous in a point such that application is bounded on

c) Prove that application is continuous in

Indice

a) Write the definition of the continuity of both applications in with then use the triangular inequality.

b) Write the definition of the continuity in with then use the triangular inequality with the form

c) Start from:

then use the triangular inequality then the previous question.

Solution

a) Let be a strictly positive real number.

Functions and being continuous in there exist two strictly positive real numbers and such that:

We then set and using the triangular inequality, we obtain:

This reasonning can be made for any strictly positive real number hence we proved that function is continuous in

b) We set and write the definition of continuity in

being an open interval and we can choose small enough such that in included in

We then use the triangular inequality : which implies:

meaning: therefore application is bounded on

c) With the triangular inequality, we obtain:

We consider an interval included in

Application

is bounded on interval hence there exists a real number which we can assume is non zero, such that:

Similarly, there exists a real non zero number such that:

We then set

Let be a strictly positive real number.

Functions and being continuous in there exists two real numbers and such that:

We also have:

We then set and we obtain:

.

The strictly positive real number being arbitrary, this infers that function is continuous in

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