Algebra bases

Take 10 minutes to prepare this exercise.

Then, if you lack ideas to begin, look at the given clue and start searching for the solution.

A detailed solution is then proposed to you.

If you have more questions, feel to ask then on the forum.

Question

Determine a sufficient and necessary condition on real numbers and and on natural integer such that equation admits a double real root.

Indice

If there is a double root, it is also a root of polynomial

Determine the hypothetic roots of polynomial must be roots of polynomial

Solution

If the polynomial defined by has a double root is a root of the polynomial and of the derivative polynomial

Real number must therefore satisfy:

andn

We infer from the second equation :

Replacing this in the first equation, we obtain:

Conversely, if equality is satisfied, the complex numbers such that are roots of the equation and its derivative equation, hence are double root of the equation. If one of these numbers is real, the equation has a real double root.

The second condition is always satisfied if is odd, hence if is even.

PrécédentPrécédentSuivantSuivant
AccueilAccueilImprimerImprimerRéalisé avec Scenari (nouvelle fenêtre)